用Octave计算矩阵分配律（3）
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矩阵分配律：\(A(B+C)=AB+AC\)
计算\( \left[ \begin{array}{ccc}
1 & 2 \\
3 & 4
\end{array} \right] \left( \left[ \begin{array}{ccc}
5 & 6 \\
7 & 8
\end{array} \right] + \left[ \begin{array}{ccc}
5 & 6 \\
7 & 8
\end{array} \right] \right) \)和\( \left[ \begin{array}{ccc}
1 & 2 \\
3 & 4
\end{array} \right] \left[ \begin{array}{ccc}
5 & 6 \\
7 & 8
\end{array} \right] + \left[ \begin{array}{ccc}
1 & 2 \\
3 & 4
\end{array} \right] \left[ \begin{array}{ccc}
5 & 6 \\
7 & 8
\end{array} \right] \)
程序代码如下
>> [1 2; 3 4] * ([5 6; 7 8] + [5 6; 7 8])
ans =
38 44
86 100
>> [1 2; 3 4] * [5 6; 7 8] + [1 2; 3 4] * [5 6; 7 8]
ans =
38 44
86 100