矩阵交换律：\(A+B=B+A\)

计算\(\left[ \begin{array}{ccc} 1 & 2 \\ 3 & 4 \end{array} \right] + \left[ \begin{array}{ccc} 5 & 6 \\ 7 & 8 \end{array} \right]\)和\(\left[ \begin{array}{ccc} 5 & 6 \\ 7 & 8 \end{array} \right] + \left[ \begin{array}{ccc} 1 & 2 \\ 3 & 4 \end{array} \right]\)

程序代码如下

>> [1 2; 3 4] + [5 6; 7 8]
ans =

  -3  -4
   4   5
>> [5 6; 7 8] + [1 2; 3 4]
ans =

    6    8
   10   12