用Octave计算矩阵结合律（1）
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矩阵结合律：\((A+B)+C=A+(B+C)\)
计算\( \left( \left[ \begin{array}{ccc}
1 & 2 \\
3 & 4
\end{array} \right] + \left[ \begin{array}{ccc}
5 & 6 \\
7 & 8
\end{array} \right] \right) + \left[ \begin{array}{ccc}
5 & 6 \\
7 & 8
\end{array} \right]\)和\( \left[ \begin{array}{ccc}
1 & 2 \\
3 & 4
\end{array} \right] + \left( \left[ \begin{array}{ccc}
5 & 6 \\
7 & 8
\end{array} \right] + \left[ \begin{array}{ccc}
5 & 6 \\
7 & 8
\end{array} \right] \right)\)
程序代码如下
>> ([1 2; 3 4] + [5 6; 7 8]) + [5 6; 7 8]
ans =
11 14
17 20
>> [1 2; 3 4] + ([5 6; 7 8] + [5 6; 7 8])
ans =
11 14
17 20